i am having difficulties with this Python regime I am developing to carry out maths, working out and also so solutions however I"m obtaining the syntaxerror: "unexpected character after line extension character in python"

this is mine code

print("Length between sides: "+str((length*length)*2.6)+" 1.5 = "+str(((length*length)*2.6)1.5)+" Units")My difficulty is through 1.5 I have actually tried 1.5 yet it doesn"t work

Using python 2.7.2


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The backslash is the line extension character the error article is talking about, and also after it, only newline characters/whitespace are allowed (before the next non-whitespace proceeds the "interrupted" line.

You are watching: Python unexpected character after line continuation character

print "This is a an extremely long string that doesn"t fit" + "on a solitary line"Outside the a string, a backslash deserve to only show up in this way. Because that division, you desire a slash: /.

If you desire to write a verbatim backslash in a string, escape that by doubling it: "\"

In her code, you"re utilizing it twice:

print("Length between sides: " + str((length*length)*2.6) + " 1.5 = " + # within a string; treated together literal str(((length*length)*2.6)1.5)+ # outside a string, treated together line cont # character, yet no newline follows -> failure " Units")

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You need to press enter after continuation character

Note: room after continuation character leader to error

cost = "apples": <3.5, 2.4, 2.3>, "bananas": <1.2, 1.8>0.9 * average(cost<"apples">) + """enter here"""0.1 * average(cost<"bananas">)

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The department operator is / fairly than .

Also, the backslash has actually a special meaning inside a Python string. Either escape that with one more backslash:

"\ 1.5 = "`or usage a raw string

r" 1.5 = "

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Well, what do you try to do? If you desire to usage division, usage "/" no "".If that is something else, define it in a bit much more detail, please.


As the others already mentioned: the department operator is / rather than **.If you wanna publish the ** character in ~ a string you need to escape it:

print("foo \")# will print: foo I think to publish the string you want I think girlfriend gonna need this code:

print("Length in between sides: " + str((length*length)*2.6) + " \ 1.5 = " + str(((length*length)*2.6)/1.5) + " Units")And this one is a more readable variation of the over (using the format method):

message = "Length in between sides: 0 \ 1.5 = 1 Units"val1 = (length * length) * 2.6val2 = ((length * length) * 2.6) / 1.5print(message.format(val1, val2))
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